0.0048 cal/(g·°C) to J/(kg·K)
Convert 0.0048 cal/(g·°c) (cal/(g·°C)) to j/(kg·k) (J/(kg·K)) with formulas and conversion tables.
cal/(g·°C)
J/(kg·K)
0.0048 cal/(g·°c) (cal/(g·°C)) = 20.09664 j/(kg·k) (J/(kg·K))
Round to:
Step-by-Step Solution
1Write the conversion factor:
1 Calorie per Gram-Celsius = 4186.8 j/(kg·k)
2Multiply the value by the conversion factor:
0.0048 × 4186.8 = 20.09664
3Result:
0.0048 cal/(g·°c) (cal/(g·°C)) = 20.09664 j/(kg·k) (J/(kg·K))
cal/(g·°C) to J/(kg·K) Conversion Table
| cal/(g·°C) | J/(kg·K) |
|---|---|
| 0.0048 cal/(g·°C) | 20.0966 J/(kg·K) |
| 1 cal/(g·°C) | 4186.8 J/(kg·K) |
| 2 cal/(g·°C) | 8373.6 J/(kg·K) |
| 5 cal/(g·°C) | 20934 J/(kg·K) |
| 10 cal/(g·°C) | 41868 J/(kg·K) |
| 20 cal/(g·°C) | 83736 J/(kg·K) |
| 50 cal/(g·°C) | 209340 J/(kg·K) |
| 100 cal/(g·°C) | 418680 J/(kg·K) |
0.0048 cal/(g·°C) in Other Units
| Unit | 0.0048 cal/(g·°C) = |
|---|---|
| cal/(g·°C) to J/(kg·K) | 20.09664 J/(kg·K) |
| cal/(g·°C) to J/(kg·°C) | 20.09664 J/(kg·°C) |
| cal/(g·°C) to kJ/(kg·K) | 0.02009664 kJ/(kg·K) |
| cal/(g·°C) to kcal/(kg·°C) | 0.0048 kcal/(kg·°C) |
| cal/(g·°C) to BTU/(lb·°F) | 0.0048 BTU/(lb·°F) |
| cal/(g·°C) to BTU/(lb·°R) | 0.0048 BTU/(lb·°R) |