0.00048 cal/(g·°C) to J/(kg·K)

Convert 0.00048 cal/(g·°c) (cal/(g·°C)) to j/(kg·k) (J/(kg·K)) with formulas and conversion tables.

cal/(g·°C)
J/(kg·K)
0.00048 cal/(g·°c) (cal/(g·°C)) = 2.009664 j/(kg·k) (J/(kg·K))
Round to:
Step-by-Step Solution
1Write the conversion factor:
1 Calorie per Gram-Celsius = 4186.8 j/(kg·k)
2Multiply the value by the conversion factor:
0.00048 × 4186.8 = 2.009664
3Result:
0.00048 cal/(g·°c) (cal/(g·°C)) = 2.009664 j/(kg·k) (J/(kg·K))

cal/(g·°C) to J/(kg·K) Conversion Table

cal/(g·°C)J/(kg·K)
0.00048 cal/(g·°C)2.00966 J/(kg·K)
1 cal/(g·°C)4186.8 J/(kg·K)
2 cal/(g·°C)8373.6 J/(kg·K)
5 cal/(g·°C)20934 J/(kg·K)
10 cal/(g·°C)41868 J/(kg·K)
20 cal/(g·°C)83736 J/(kg·K)
50 cal/(g·°C)209340 J/(kg·K)
100 cal/(g·°C)418680 J/(kg·K)

0.00048 cal/(g·°C) in Other Units

Unit0.00048 cal/(g·°C) =
cal/(g·°C) to J/(kg·K)2.009664 J/(kg·K)
cal/(g·°C) to J/(kg·°C)2.009664 J/(kg·°C)
cal/(g·°C) to kJ/(kg·K)0.002009664 kJ/(kg·K)
cal/(g·°C) to kcal/(kg·°C)0.00048 kcal/(kg·°C)
cal/(g·°C) to BTU/(lb·°F)0.00048 BTU/(lb·°F)
cal/(g·°C) to BTU/(lb·°R)0.00048 BTU/(lb·°R)

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